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高斯整數(shù)環(huán)的一道典型習(xí)題

2023-08-20 01:20 作者:自函子  | 我要投稿

設(shè)?z 是高斯整數(shù), 且?%5Cgcd(%5CRe%20z%2C%5CIm%20z)%3D1 , 證明?%5Cmathbb%7BZ%7D%5Bi%5D%2F%5Clangle%20z%5Crangle%20 恰好有?%5Cleft%7Cz%5Cright%7C%5E2 個元素.

證明: 不妨設(shè)其實部, 虛部為?a%2Cb?. 此時由?%5Crm%7BBezout%7D?定理,?%5Cexists%20%5C%2C%20s%2Ct%20%5C%2C%5Cin%5C%2C%5Cmathbb%7BZ%7D?, 滿足?as%2Bbt%3D1?.

則有? ? ? ??z(t%2Bsi)%3Dat-bs%2B%5Coverbrace%7Bas%2Bbt%7D%5E%7B1%7Di%3Dat-bs%2Bi%20%20%5Cequiv%200%20%5Cpmod%7Bz%7D%20%5Cimplies%20i%20%5Cequiv%20bs-at%20%5Cpmod%7Bz%7D%20%5C%5C

命環(huán)同態(tài)為 ?%5Cvarphi%3A%20%5Cmathbb%7BZ%7D%5Cto%5Cmathbb%7BZ%7D%5Bi%5D%2F%5Clangle%20z%5Crangle .? 考慮?%5Cforall%20%5C%2Cx%2Byi%5Cin%20%5Cmathbb%7BZ%7D%5Bi%5D%2C%5C%2C%5C%2Cx%2Byi%20%5Cequiv%20x%2By(bs-at)%20%5Cin%20%5Cmathbb%7BZ%7D%5Cpmod%7Bz%7D. 即是說像中任意元素必與一整數(shù)對應(yīng), 故 %5Cvarphi 滿.?

%20%5Cforall%20%5C%2C%20u%20%5Cin%5Cker%5Cvarphi%2C%5C%2C%20a%2Bbi%5Cmid%20u%20%5Cimplies%20%5Cdfrac%7Bu%7D%7Ba%2Bbi%7D%20%5Cin%20%5Cmathbb%7BZ%7D%5Bi%5D%5C%5C%0A%20%5Cimplies%20%20%20%5Cdfrac%7Bu(a-bi)%7D%7B%5Cleft%7Cz%5Cright%7C%5E2%7D%5Cin%20%5Cmathbb%7BZ%7D%5Bi%5D%20%5Cimplies%5Cleft%7Cz%5Cright%7C%5E2%20%5Cmid%20%5Cgcd(ua%2C%20ub)%20%5Cimplies%20%5Cleft%7Cz%5Cright%7C%5E2%5Cmid%20u%5Cgcd(a%2Cb)%3Du

這即是說?%5Cker%5Cvarphi%20%3D%5Cleft%7Cz%5Cright%7C%5E2%5Cmathbb%7BZ%7D? .?從而依同態(tài)基本定理有

%5Ctext%7BIm%7D%5Cvarphi%5Ccong%20%5Cmathbb%7BZ%7D%2F%5Cker%5Cvarphi%3D%20%5Cmathbb%7BZ%7D%2F%5Cleft%7Cz%5Cright%7C%5E2%5Cmathbb%7BZ%7D%20%5C%5C?

高斯整數(shù)環(huán)的一道典型習(xí)題的評論 (共 條)

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