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leetcode 442. Find All Duplicates in an Array

2022-02-18 12:53 作者:您是打尖兒還是住店呢  | 我要投稿

Given an integer array?nums?of length?n?where all the integers of?nums?are in the range?[1, n]?and each integer appears?once?or?twice, return?an array of all the integers that appears?twice.

You must write an algorithm that runs in?O(n)?time and uses only constant extra space.

?

Example 1:

Input: nums = [4,3,2,7,8,2,3,1]Output: [2,3]

Example 2:

Input: nums = [1,1,2]Output: [1]

Example 3:

Input: nums = [1]Output: []

?

Constraints:

  • n == nums.length

  • 1 <= n <= 105

  • 1 <= nums[i] <= n

  • Each element in?nums?appears?once?or?twice.


Success

Details?

Runtime:?39 ms, faster than?10.65%?of?Java?online submissions for?Find All Duplicates in an Array.

Memory Usage:?68.4 MB, less than?18.64%?of?Java?online submissions for?Find All Duplicates in an Array.


leetcode 442. Find All Duplicates in an Array的評論 (共 條)

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